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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 132590Generated: October 27, 2026

Benzhydryl-2-methyl-1H-indol-7-yl-ether → 2-methyl-1H-indol-7-ol

https://huagongshe.com/reaction/132590

Reaction equation

Participants

RoleNameHCIDCharge
ReactantBenzhydryl-2-methyl-1H-indol-7-yl-etherHCID 69197050—
CatalystPalladium hydroxideHCID 9942167—
SolventMethanolHCID 887—
SolventTolueneHCID 1140—
Product2-methyl-1H-indol-7-olHCID 1876522250.1%

Reaction Steps

Benzhydryl-2-methyl-1H-indol-7-yl-ether (85 mg, 0.271 mmol) in methanol (MeOH) (3 mL) and toluene (3 mL) was hydrogenated in the presence of 20% palladium hydroxide (Pd(OH)2) (40 mg) at 40 p.s.i for 70 min at room temperature. The catalyst was filtered off, filtrate concentrated and the residue purified by silica gel flash chromatography to give subtitled compound (20 mg).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07388020B2
Source datasetuspto-grants-2008_06
ORD IDord-3988c418b5d546f7bfa026cb218613d3
Source noteuspto-grants-2008_06