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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1351259Generated: November 2, 2026

Hydrochloric Acid → 3-(4-Fluoro-3-methoxyphenyl)propanoic acid

https://huagongshe.com/reaction/1351259

Reaction equation

Participants

RoleNameHCIDCharge
ReactantHydrochloric AcidHCID 313—
ReactantSodium HydroxideHCID 14798—
Reactant3-(4-Fluoro-3-methoxyphenyl)acrylic acid ethyl esterHCID 69414712—
CatalystHCID 178418390HCID 178418390—
SolventEthanolHCID 702—
SolventEthyl AcetateHCID 8857—
Product3-(4-Fluoro-3-methoxyphenyl)propanoic acidHCID 2109860684.7%

Reaction Steps

To a solution of 3-(4-fluoro-3-methoxyphenyl)acrylic acid ethyl ester (4.54 g) in ethyl acetate (20 mL)-ethanol (20 mL) was added 10% percent palladium-carbon (450 mg). After stirring under hydrogen gas atmosphere for 2.5 hours, the metal catalyst was removed by filtration, the solvent was removed by evaporation, and an oily substance (4.64 g) was obtained. This was dissolved in a solution of ethanol (40 mL), an aqueous solution of 5N sodium hydroxide was added, and the solution was stirred at room temperature for 30 minutes. After the solution was acidified by adding 5N hydrochloric acid (21 mL), the solid precipitated. After diluting with water, the solid was collected by filtration, dried by aeration, and a colorless solid (3.4 g) was obtained.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07217723B2
Source datasetuspto-grants-2007_05
ORD IDord-1ee790a2cc374549946077db4673c300
Source noteuspto-grants-2007_05