Sodium Hydroxide → HCID 69509116, compound
Reaction equation
C([O:3][C:4](=[O:41])[CH2:5][C@@H:6]([NH:19][C:20]1[C:25]([C:26]2[CH:31]=[CH:30][CH:29]=[CH:28][C:27]=2[F:32])=[CH:24][N:23]=[C:22]([N:33]([CH:35]2[CH2:40][CH2:39][CH2:38][CH2:37][CH2:36]2)[CH3:34])[N:21]=1)[C:7]1[CH:12]=[CH:11][C:10]([O:13][C:14]([N:16]([CH3:18])[CH3:17])=[O:15])=[CH:9][CH:8]=1)C.[OH-].[Na+]>CO.O>[F:32][C:27]1[CH:28]=[CH:29][CH:30]=[CH:31][C:26]=1[C:25]1[C:20]([NH:19][C@@H:6]([C:7]2[CH:8]=[CH:9][C:10]([O:13][C:14]([N:16]([CH3:17])[CH3:18])=[O:15])=[CH:11][CH:12]=2)[CH2:5][C:4]([OH:41])=[O:3])=[N:21][C:22]([N:33]([CH:35]2[CH2:40][CH2:39][CH2:38][CH2:37][CH2:36]2)[CH3:34])=[N:23][CH:24]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 22 °C
Procedure
To a solution of (R)-3-(5-(2-fluorophenyl)-2-(N-cyclohexyl-N-methylamino)pyrimidin-4-ylamino)-3-(4-(dimethylaminocarbonyl)oxyphenyl)propanoic acid ethyl ester (1.0 eq) in 3:1 MeOH/H2O was added 1M NaOH (2.5 eq). The mixture was stirred at 22° C. for 6 hr, and then the MeOH and H2O were evaporated. The residue was partitioned between Et2O and H2O, and then the separated aqueous layer was acidified to pH=3 by addition of 0.1 M H3PO4. The aqueous layer was extracted three times with 3:1 CHCl3/iPrOH, and then the CHCl3/iPrOH extracts were treated with MgSO4, filtered and evaporated to give (R)-3-(5-(2-fluorophenyl)-2-(N-cyclohexyl-N-methylamino)pyrimidin-4-ylamino)-3-(4-(dimethylaminocarbonyl)oxyphenyl)propanoic acid.
Workup
- customthe MeOH and H2O were evaporated
- customThe residue was partitioned between Et2O and H2O
- additionthe separated aqueous layer was acidified to pH=3 by addition of 0.1 M H3PO4
- extractionThe aqueous layer was extracted three times with 3:1 CHCl3/iPrOH
- additionthe CHCl3/iPrOH extracts were treated with MgSO4
- filtrationfiltered
- customevaporated
Sources & evidence
- ORD record
- ord-45b58dbda7094405821806288a2c771d
- Source dataset
- uspto-grants-2007_05
- Patent number
- US07223762B2
Reaction notes
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