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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1367719Generated: October 25, 2026

Imidazole → 17-Acetoxy-heptadecyl iodide

https://huagongshe.com/reaction/1367719

Reaction equation

Participants

RoleNameHCIDCharge
ReactantImidazoleHCID 795—
ReactantIodineHCID 807—
ReactantTriphenylphosphineHCID 11776—
Reactant17-Acetoxy-heptadecanolHCID 86625640—
SolventBenzeneHCID 241—
SolventDichloromethaneHCID 6344—
Product17-Acetoxy-heptadecyl iodideHCID 8662564199.2%

Reaction Conditions

Temperature0 °C

Reaction Steps

17-Acetoxy-heptadecanol (4.4 g, 13.99 mmol), Ph3P (4.4 g, 16.78 mmol) and imidazole (1.57 g, 23.08 mmol) were dissolved in the mixture of CH2Cl2 (40 ml) and benzene (20 ml). The mixture was cooled to 0° C. and solid I2 (4.26 g, 16.78 mmol) was added in one portion. The mixture was stirred at 0° C. for 15 min and at room temperature for 30 min. The reaction was quenched by the addition of EtOH (1.5 ml), stirred for 10 min at room temperature, diluted with hexane-EtOAc (1:1) mixture and washed with aqueous NaHCO3—Na2S2O3 solution. The organic extract was dried Na2SO4 and evaporated. Residue was stirred with hexane (300 ml) for 20 min and the suspension was filtered to remove Ph3PO. The filtrate was evaporated and the residue was chromatographed on silica gel in hexane-EtOAc (98:2) to give 17-acetoxy-heptadecyl iodide (5.89 g, 99%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07893286B2
Source datasetuspto-grants-2011_02
ORD IDord-fee124341e2549b0aad8119c57f1a20c
Source noteuspto-grants-2011_02