HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1368691Generated: October 27, 2026
Chlorotrimethylsilane → N2-hexanoyl-9-(4-hydroxy-3-hydroxymethylbut-1-yl)guanine
https://huagongshe.com/reaction/1368691
Participants
| Role | Name | HCID | Charge |
|---|
| Reactant | Chlorotrimethylsilane | HCID 6397 | — |
| Reactant | Hexanoyl chloride | HCID 67340 | — |
| Reactant | 1,8-Diazabicyclo(5.4.0)undec-7-ene | HCID 81184 | — |
| Reactant | Penciclovir | HCID 135398748 | — |
| Solvent | Methanol | HCID 887 | — |
| Solvent | Water | HCID 962 | — |
| Solvent | Pyridine | HCID 1049 | — |
| Product | N2-hexanoyl-9-(4-hydroxy-3-hydroxymethylbut-1-yl)guanine | HCID 136018077 | 14.2% |
Reaction Steps
To a suspension of 9-(4-hydroxy-3-hydroxymethylbut-1-yl)-guanine (0.25 g, 1.0 mmol) in pyridine (5 ml) was added chlorotrimethylsilane (0.32 ml, 2.5 mmol) and the mixture was stirred for 15 minutes. To this mixture was added hexanoyl chloride (0.18 ml, 1.3 mmol) and the mixture was stirred for 20 minutes. Methanol (2 ml) was then added and the mixture was stirred for a further 20 minutes. 1,8-Diazabicyclo[5.4.0]undec-7-ene (0.57 ml, 3.8 mmol) and water (0.5 ml) were added and the solvent was removed. The residue was purified by column chromatography on silica gel eluting with chloroform-methanol (4:1). Product containing fractions were pooled and the solvent removed. The residue was taken up in water and passed through C18-Sep-pak cartridges to afford N2-hexanoyl-9-(4-hydroxy-3-hydroxymethylbut-1-yl)guanine (50 mg, 14%), m.p. 86-88° C.; νmax (KBr) 3400, 2960, 2940, 1675, 1610, and 1560 cm−1; δH [(CD3)2SO] 0.88 (3H, t, J 6.7 Hz, CH3) 1.29 (4H, m, CH3(CH2)2), 1.46 (1H, m, 3′-H), 1.60 (2H, m, CH2CH2CO), 1.77 (2H, q, J 7.1 Hz, 2′-H), 2.46 (2H, t, J 7.4 Hz, CH2CO) 3.3-3.5 (4H, m, 2×4′-H), 4.13 (2H, t, J 7.4 Hz, 1′-H), 4.41 (2H, t, J 4.7 Hz, D2O exchangeable, 2×OH), 7.98 (1H, s, 8-H), 11.65 (1H, br, D2O exchangeable, NH), and 12.01 (1H, br, D2O exchangeable, NH); (Found: C, 53.64; H, 7.56; N, 18.95%; C16H25N5O4.0.5H2O requires: C, 53.32; H, 7.27; N, 19.43%).
Provenance & Evidence
| DOI | 10.6084/m9.figshare.5104873.v1 |
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| Patent number | US06573378B1 |
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| Source dataset | uspto-grants-2003_06 |
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| ORD ID | ord-e788992d9dc84eb88a0f184ccd22d39a |
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| Source note | uspto-grants-2003_06 |
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