1,6-Hexanediol → HCID 135967528, compound

HRID 1369325Notes

Reaction equation

HRID 1369325 reaction equation
[OH:1][C:2]1[CH:3]=[C:4]([CH:14]=[CH:15][C:16]=1[C:17](=[S:30])[C:18]1[CH:23]=[CH:22][C:21]([C:24]2[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=2)=[CH:20][CH:19]=1)[O:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][C:11]([OH:13])=[O:12].[CH2:31]([OH:38])[CH2:32][CH2:33][CH2:34][CH2:35][CH2:36][OH:37]>>[OH:1][C:2]1[CH:3]=[C:4]([CH:14]=[CH:15][C:16]=1[C:17](=[S:30])[C:18]1[CH:19]=[CH:20][C:21]([C:24]2[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=2)=[CH:22][CH:23]=1)[O:37][CH2:36][CH2:35][CH2:34][CH2:33][CH2:32][C:31]([O:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][O:12][C:11](=[O:13])[CH2:10][CH2:9][CH2:8][CH2:7][CH2:6][O:5][C:4]1[CH:14]=[CH:15][C:16]([C:17](=[S:30])[C:18]2[CH:19]=[CH:20][C:21]([C:24]3[CH:25]=[CH:26][CH:27]=[CH:28][CH:29]=3)=[CH:22][CH:23]=2)=[C:2]([OH:1])[CH:3]=1)=[O:38]

Participants

3

Procedure

Following the general procedure of Example 13 or Example 17, the title compound is prepared by reacting an equivalent amount of the acid compound of Example 16 with a half equivalent amount of 1,6-hexanediol.

Sources & evidence

ORD record
ord-db25d47d1d494e09af4fbc7d88bbbe0f
Source dataset
uspto-grants-2003_06
Patent number
US06576797B1

Reaction notes

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