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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1370601Generated: October 25, 2026

9,9'-Bianthryl → 10-bromo-9,9'-Bianthracene

https://huagongshe.com/reaction/1370601

Reaction equation

Participants

RoleNameHCIDCharge
Reactant9,9'-BianthrylHCID 66105—
ReactantN-bromobutanimideHCID 67184—
SolventCarbon TetrachlorideHCID 5943—
Product10-bromo-9,9'-BianthraceneHCID 1519599781.8%

Reaction Steps

In a flask were placed 35 g of 9,9′-bianthryl, 18.0 g of N-bromosuccinimide and 500 mL of carbon tetrachloride, and the mixture was stirred overnight. The reaction mixture was filtered, the filtrate was passed through a column filled with alumina. Carbon tetrachloride was evaporated from the solution under a reduced pressure, and then the residue was recrystallized from petroleum ether, to give 35 g(yield: 80%) of 10-bromo-9,9′-bianthryl. Then, in a 100 mL three-necked flask were placed 18.3 g of 10-bromo-9,9′-bianthryl, 10 g of diphenylamine, 8.5 g of potassium carbonate, 0.2 g of copper powder and 50 mL of nitrobenzene, and the mixture was stirred at 200° C. for 30 hours. After completion of the reaction, toluene was added to the mixture. The mixture was filtered to remove inorganics. Toluene and nitrobenzene were evaporated under a reduced pressure. The residue was purified by column chromatography on silica gel eluting with a 1:2 mixture of toluene and ligroin, to give 15 g(yield: 60%) of 10-diphenylamino-9,9′-bianthryl.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06582837B1
Source datasetuspto-grants-2003_06
ORD IDord-2482f85755e94721ab4df49beaf32d01
Source noteuspto-grants-2003_06