HRID1376250

反应详情

EQUATION

反应方程式

HRID 1376250 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Compound 21 was prepared from Compound 14 using the same procedure as described above for Compound 16. Yield 1.11 g (61.9%) as a viscous oil. Rf=0.28 (hexane:diethyl ether 6:4); 1H NMR δ 6.38 (d, J=2 Hz, 2H), 6.17 (t, J=2.25 Hz, 1H), 4.82 (br s, 2H), 1.71–1.68 (m, 2H), 1.63–1.60 (m, 1H), 1.53–1.51 (m, 2H), 1.42–1.36 (m, 1H), 1.17 (s, 6H), 1.16–1.03(m, 3H), 0.94–0.86 (m, 2H); 13C NMR δ 156.32, 154.45, 106.56, 100.02, 49.21, 40.85, 28.12, 27.39, 26.91, 25.39, 14.40; MS: (ESI, Neg.) m/z 233 ([M−H]−).