HRID1384362

反应详情

EQUATION

反应方程式

HRID 1384362 的结构方程式

PROCEDURE

实验过程

Following the same procedure as that described in Example 34A, the title compound of example 31 (100 mg, 0.203 mmol) was treated with BBr3 in CH2Cl2 (1M, 1.02 ml, 1.02 mmol) to give the title compound (64 mg, 67% yield).