HRID13946

反应详情

EQUATION

反应方程式

HRID 13946 的结构方程式

PROCEDURE

实验过程

Treatment of 5-allyl-6-chloroindan-4-ol (4.5 g, 0.0216 mol) with sodium hydride (60 wt. %, 1.32 g, 0.033 mol) followed by benzyl bromide (6.0 g, 0.035 mol) generally according to the procedure described for Intermediate 38 gave 5.76 g (89%) of 5-allyl-4-(benzyloxy)-6-chloroindane as a colorless oil. 1H NMR (CDCl3) 8H 7.40 (m, 5H); 7.05 (s, 1H); 6.00 (m, 1H); 5.00(m, 2H); 4.90 (s, 2H); 3.53 (dd, 2H); 2.90 (m, 4H); 2.05 (m, 2H).