(R)-1-(4-Fluorophenyl)ethanol → HCID 66575809, compound

HRID 1405237Notes

Reaction equation

HRID 1405237 reaction equation
F[C:2]1[CH:7]=[C:6]([F:8])[CH:5]=[CH:4][C:3]=1[C:9]1[N:14]=[CH:13][N:12]=[C:11]([NH:15][C:16]2[CH:21]=[CH:20][CH:19]=[C:18]([CH2:22][S:23]([CH3:26])(=[O:25])=[O:24])[CH:17]=2)[N:10]=1.[F:27][C:28]1[CH:36]=[CH:35][C:31]([C@H:32]([OH:34])[CH3:33])=[CH:30][CH:29]=1>>[F:8][C:6]1[CH:5]=[CH:4][C:3]([C:9]2[N:14]=[CH:13][N:12]=[C:11]([NH:15][C:16]3[CH:21]=[CH:20][CH:19]=[C:18]([CH2:22][S:23]([CH3:26])(=[O:25])=[O:24])[CH:17]=3)[N:10]=2)=[C:2]([O:34][C@@H:32]([C:31]2[CH:35]=[CH:36][C:28]([F:27])=[CH:29][CH:30]=2)[CH3:33])[CH:7]=1

Participants

3

Reactant 2

HCID 852998(R)-1-(4-Fluorophenyl)ethanolHCID 709765244-(2,4-difluorophenyl)-N-{3-[(methylsulfonyl)methyl]phenyl}-1,3,5-triazin-2-amine

Product 1

HCID 66575809HCID 66575809, compound

Procedure

Starting with 4-(2,4-difluorophenyl)-N-{3-[(methylsulfonyl)methyl]phenyl}-1,3,5-triazin-2-amine (50 mg; 0.129 mmol), intermediate 42.1, and (R)-4-fluoro-α-methylbenzyl alcohol (74.4 mg; 0.515 mmol), example 67 was prepared analogously to the procedure for the preparation of example 42.

Workup

  1. customwas prepared analogously to the procedure for the preparation of example 42

Sources & evidence

ORD record
ord-738e7d30dbf6413aa1ecd9b1224eff36
Source dataset
uspto-grants-2014_12
Patent number
US08916557B2

Reaction notes

Loading…