4-Fluorobenzylamine → HCID 136377094, compound

HRID 1409584Notes

Reaction equation

CO[C:3]([C:5]1[N:6]=[C:7]([CH2:13][C:14]2[CH:19]=[CH:18][CH:17]=[CH:16][C:15]=2[Br:20])[NH:8][C:9](=[O:12])[C:10]=1[OH:11])=[O:4].[F:21][C:22]1[CH:29]=[CH:28][C:25]([CH2:26][NH2:27])=[CH:24][CH:23]=1>>[F:21][C:22]1[CH:29]=[CH:28][C:25]([CH2:26][NH:27][C:3]([C:5]2[N:6]=[C:7]([CH2:13][C:14]3[CH:19]=[CH:18][CH:17]=[CH:16][C:15]=3[Br:20])[NH:8][C:9](=[O:12])[C:10]=2[OH:11])=[O:4])=[CH:24][CH:23]=1

Participants

Reactant 2

HCID 673264-Fluorobenzylamine

HCID 136377092HCID 136377092, compound

Product 1

HCID 136377094HCID 136377094, compoundYield 70.6%

Procedure

The compound was prepared according to the same procedure as in Example 21 using 2-(2-bromo-benzyl)-5-hydroxy-6-oxo-1,6-dihydro-pyrimidine-4-carboxylic acid methyl ester (0.08 g; 0.236 mmol) and 4-fluorobenzylamine (0.5 ml; 4.4 mmol). This gave the title compound as a white solid (0.072 g; 70%). LCMS: m/z=433 (MH+).

Workup

customThe compound was prepared

Sources & evidence

ORD record: ord-b59af9a910c449aa942c1c879556c240
Source dataset: uspto-grants-2014_12
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US08921388B2

Reaction notes

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