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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1418060Generated: November 3, 2026

Aluminium lithium hydride → 4-(4-Chlorophenyl)-2-fluoro-4-methylpent-2-enol

https://huagongshe.com/reaction/1418060

Reaction equation

Participants

RoleNameHCIDCharge
ReactantAluminium lithium hydrideHCID 21226445—
ReactantMethyl 4-(4-chlorophenyl)-2-fluoro-4-methylpent-2-enoateHCID 54161401—
SolventDiethyl EtherHCID 3283—
Product4-(4-Chlorophenyl)-2-fluoro-4-methylpent-2-enolHCID 5379104592%

Reaction Steps

The method of Example 6 was repeated using methyl 4-(4-chlorophenyl)-2-fluoro-4-methylpent-2-enoate (Example 3) (0.56 g), diethyl ether (20 ml) and lithium aluminium hydride (0.21 g) to yield the title compound (0.35 g, 92%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05880162
Source datasetuspto-grants-1999_03
ORD IDord-313e3d51296148618919c1cf031aef9a
Source noteuspto-grants-1999_03