Hydrochloric Acid → 2-(4-(Quinolin-2-ylmethoxy)phenyl)acetic acid

Participants

Reaction Steps

To a solution of ethyl 2-(4-(quinolin-2-ylmethoxy)phenyl)acetate (8 g, 0.02 mol) in MeOH: THF (300 mL; 1:1) was added LiOH.H2O (5.21 g, 0.124 mol) and the mixture was stirred at RT for 1 h. The reaction mixture was then concentrated in vacuo to obtain the crude compound. The crude material was acidified with HCl (IN), filtered and dried in vacuo to afford 2-(4-(quinolin-2-ylmethoxy)phenyl)acetic acid (7.0 g, 95%) as a solid.

Provenance & Evidence