HRID1440986

反应详情

EQUATION

反应方程式

HRID 1440986 的结构方程式

PROCEDURE

实验过程

The synthesis of intermediates leading to different values of m and X is within the capability of one skilled in the art. Example 3 details the method of making the compound wherein X is --CH(CH3)-- and m is 2. This synthesis starts with the reduction of 2-(4-chlorophenyl)propionic acid with lithium aluminum hydride, producing 2-(4-chlorophenyl)propanol. Oxidation of this alcohol with pyridinium chlorochromate in methylene chloride produces 2-(4-chlorophenyl)propionaldehyde. This aldehyde is then reacted with (carbethoxymethylene)triphenylphosphorane, yielding ethyl 4-(4-chlorophenyl)-2-pentenoate. Hydrogenation of this ester in the presence of platinum oxide produces ethyl 4-(4-chlorophenyl)pentanoate which is then hydrolyzed with sodium hydroxide to the corresponding pentanoic acid (II). The remaining steps of this synthesis are shown in Schema 1.

WORKUP

后处理

  1. customThe synthesis of intermediates