1H-Indazol-4-amine, 1-methyl- → HCID 68682622, compound

HRID 1443200Notes

Reaction equation

HRID 1443200 reaction equation
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][C:4]=1[C:9]([CH3:20])([CH3:19])[CH2:10][C:11]([OH:18])([C:14]([F:17])([F:16])[F:15])[CH:12]=O.[NH2:21][C:22]1[CH:30]=[CH:29][CH:28]=[C:27]2[C:23]=1[CH:24]=[N:25][N:26]2[CH3:31]>[Ti](Cl)(Cl)(Cl)Cl>[CH3:31][N:26]1[C:27]2[C:23](=[C:22]([NH:21][CH:12]3[C:5]4[C:4](=[C:3]([O:2][CH3:1])[CH:8]=[CH:7][CH:6]=4)[C:9]([CH3:20])([CH3:19])[CH2:10][C:11]3([C:14]([F:15])([F:17])[F:16])[OH:18])[CH:30]=[CH:29][CH:28]=2)[CH:24]=[N:25]1

Participants

4

Reactant 2

HCID 1538381H-Indazol-4-amine, 1-methyl-HCID 179890984-(2-Methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal

Product 1

HCID 68682622HCID 68682622, compoundYield 23.4%

Reagents, catalysts & solvents 1

HCID 24193Titanium TetrachlorideCatalyst

Procedure

Analogously to Example 3, the corresponding imine is produced starting from 296 mg of 4-(2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal and 150 mg of 4-amino-1-methylindazole. By reaction of 100 mg of the imine with 0.5 ml of titanium tetrachloride, 100 mg of the title compound is obtained.

Sources & evidence

ORD record
ord-1898c088d1084eebae9e79cb64b956c8
Source dataset
uspto-grants-2010_02
Patent number
US07659297B2

Reaction notes

Loading…