HRID1443214

反应详情

EQUATION

反应方程式

HRID 1443214 的结构方程式

PROCEDURE

实验过程

Analogously to Example 10, the corresponding imine is produced starting from 500 mg of 4-(2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal and 302 mg of 5-amino-2-methylphthalazin-1-one. As in Example 2, 158 mg of 5-{[2-hydroxy-4,4-dimethyl-5-methoxy-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one as fraction 1, 66 mg of 5-{[2,5-dihydroxy-4,4-dimethyl-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one, diastereomer A as fraction 4, and 77 mg of 5-{[2,5-dihydroxy-4,4-dimethyl-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one, diastereomer A as fraction 5 are obtained by reaction of 570 mg of imine with 6.4 ml of BBr3 (1 M in dichloromethane).