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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1443677Generated: October 25, 2026

Methyl iodide → 7-[3-(2-Methoxyphenyl)pyrazol-1-yl]heptanoic acid ethyl ester

https://huagongshe.com/reaction/1443677

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantSodium hydrideHCID 24758—
Reactant7-[3-(2-Hydroxyphenyl)pyrazol-1-yl]heptanoic acid ethyl esterHCID 136206529—
SolventTetrahydrofuranHCID 8028—
Product7-[3-(2-Methoxyphenyl)pyrazol-1-yl]heptanoic acid ethyl esterHCID 6848899076%

Reaction Steps

Add sodium hydride (900 mg, 18 mmol, 60% suspension in mineral oil) to a suspension of 7-[3-(2-hydroxyphenyl)pyrazol-1-yl]heptanoic acid ethyl ester (4.73 g, 15 mmol) and iodomethane (1.1 mL, 18 mmol) in THF (70 mL) at 0° C. under nitrogen and warm the mixture to room temperature to stir for 12 hours. Remove the solvent under reduced pressure, dilute the residue with ethyl acetate (150 mL), wash with water (100 mL), and dry over sodium sulfate. Remove the solvent under reduced pressure and purify the residue by flash column chromatography on silica gel, eluting with hexanes/ethyl acetate (9:1), to provide 7-[3-(2-Methoxyphenyl)pyrazol-1-yl]heptanoic acid ethyl ester (3.75 g, 76%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07662771B2
Source datasetuspto-grants-2010_02
ORD IDord-66f603671d2d47fb94cb4a7c4f0e095f
Source noteuspto-grants-2010_02