Allyl bromide → 3-[1-(6,7-Dimethoxy-4-quinazolinyl)-4-piperidinyl]-1,2,3,4-tetrahydro-6-nitro-2,4-dioxo-1-(2-propenyl)-quinazoline

Participants

Reaction Steps

The procedure similar to that described in Example 1 was repeated, except that 334.6 mg (0.7 mmol) of Compound 24 was used and allyl bromide was used in place of methyl iodide. As a result, 192.8 mg (yield: 53%) of Compound 5 was obtained as pale yellow crystals.

Provenance & Evidence