HRID1451912

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：COc1cc2ncnc(N3CCC(n4c(=O)c5cc(C)ccc5n(C)c4=O)CC3)c2cc1O

HCID22923375

未命名化合物

PRODUCTS

生成物

结构：CCOC(=O)COc1cc2c(N3CCC(n4c(=O)c5cc(C)ccc5n(C)c4=O)CC3)ncnc2cc1OC

HCID22923401

未命名化合物

收率 54%

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 500.0 mg (1.12 mmol) of Compound 90 obtained in Example 80 was used in place of Compound 24 and ethyl bromoacetate was used in place of methyl iodide. As a result, 323.3 mg (yield: 54%) of Compound 94 was obtained as white crystals.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-b5a21db0e8a74e1bba32f65f0ab99a1a
来源数据集: uspto-grants-1997_02
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05605900
来源说明: uspto-grants-1997_02

反应 SMILES

[OH:1][C:2]1[CH:3]=[C:4]2[C:9](=[CH:10][C:11]=1[O:12][CH3:13])[N:8]=[CH:7][N:6]=[C:5]2[N:14]1[CH2:19][CH2:18][CH:17]([N:20]2[C:29](=[O:30])[C:28]3[C:23](=[CH:24][CH:25]=[C:26]([CH3:31])[CH:27]=3)[N:22]([CH3:32])[C:21]2=[O:33])[CH2:16][CH2:15]1.Br[CH2:35][C:36]([O:38][CH2:39][CH3:40])=[O:37]>>[CH2:39]([O:38][C:36]([CH2:35][O:1][C:2]1[CH:3]=[C:4]2[C:9](=[CH:10][C:11]=1[O:12][CH3:13])[N:8]=[CH:7][N:6]=[C:5]2[N:14]1[CH2:19][CH2:18][CH:17]([N:20]2[C:29](=[O:30])[C:28]3[C:23](=[CH:24][CH:25]=[C:26]([CH3:31])[CH:27]=3)[N:22]([CH3:32])[C:21]2=[O:33])[CH2:16][CH2:15]1)=[O:37])[CH3:40]