Z-Pal-N(Me)Bzl → H-Pal-N(Me)Bzl

HRID 1458204Notes

Reaction equation

HRID 1458204 reaction equation
[NH:1](C(OCC1C=CC=CC=1)=O)[C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1>CO.[Pd].[C]>[NH2:1][C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1

Participants

4

Procedure

2.68 g of Z-Pal-N(Me)Bzl (6.85 mMol) are dissolved in 30 ml of MeOH and after adding 0.3 g of Pd-carbon hydrogenated for 5 hours at ambient temperature and 5 bar. Then, the mixture is filtered, the filtrate is concentrated on the rotary evaporator, the residue is dissolved in ether, filtered and the filtrate is again concentrated. H-Pal-N(Me)Bzl is obtained as a light green oil.

Workup

  1. filtrationThen, the mixture is filtered
  2. concentrationthe filtrate is concentrated on the rotary evaporator
  3. dissolutionthe residue is dissolved in ether
  4. filtrationfiltered
  5. concentrationthe filtrate is again concentrated

Sources & evidence

ORD record
ord-e261218c97c44ffaa596b7aaa9913394
Source dataset
uspto-grants-1998_12
Patent number
US05849918

Reaction notes

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