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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 1460867생성일: 2026년 10월 25일

Hydrofluoric Acid → 2,3,4,5-Tetrachlorobenzoyl fluoride

https://huagongshe.com/reaction/1460867

반응식

참여 물질

역할이름HCID투입량
반응물Hydrofluoric AcidHCID 14917—
반응물ChlorineHCID 24526—
반응물Potassium FluorideHCID 522689—
반응물2,3,4,5-Tetrachlorobenzoyl chlorideHCID 5463797—
생성물2,3,4,5-Tetrachlorobenzoyl fluorideHCID 13565014—

반응 단계

The quantity of potassium fluoride to be used depends on the number of chlorine atoms which are to be exchanged. At least one mole of KF is used, but in general 1.1-1.5 mole, for 1 chlorine atom. A maximum of 2 moles of KF is used for 1 chlorine; beyond this, the quantity of KF has virtually no effect on the degree of fluorination, and the process becomes uneconomic. However, it is possible to save part of the costly KF when the 2,3,4,5-tetrachlorobenzoyl chloride is previously fluorinated with hydrofluoric acid, and the 2,3,4,5-tetrachlorobenzoyl fluoride, which results in virtually quantitative yield from this reaction, is used for the Cl/F exchange reaction with KF. Because of the greater activation by the more electronegative fluorocarbonyl group, its greater thermal stability, and the reduced load of KCl in the reaction mixture, this two-stage fluorination leads to an overall improvement in the balance of the nuclear fluorination.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US05072038
출처 데이터셋uspto-grants-1991_12
ORD IDord-127ca677841c406bb2ab55925c0d7ccb
출처 메모uspto-grants-1991_12