Terephthalic Acid → Disodium terephthalate

HRID 1461947Notes

Reaction equation

HRID 1461947 reaction equation
S([O-])([O-])(=O)=O.[Na+:6].[Na+].[C:8]([OH:19])(=[O:18])[C:9]1[CH:17]=[CH:16][C:12]([C:13]([OH:15])=[O:14])=[CH:11][CH:10]=1.[OH-].[Na+]>[Hg].O>[C:8]([O-:19])(=[O:18])[C:9]1[CH:17]=[CH:16][C:12]([C:13]([O-:15])=[O:14])=[CH:11][CH:10]=1.[Na+:6].[Na+:6]

Participants

6

Procedure

An aqueous solution of 2 (wt)% sodium sulfate, approximately 0.14 moles/liter of water, was used as the pH neutral anolyte. The catholyte consisted of water, terephthalic acid, and sodium hydroxide. The cathode was mercury. The terephthalic acid reacted with the sodium hydroxide to form disodium terephthalate. The pH at the beginning of the electrochemical reaction was 7.2. As the reaction progressed, the pH increased to 12.9 at the end of the electrolysis. No attempt was made to maintain a neutral pH. Results are in Table I.

Sources & evidence

ORD record
ord-cf7bd1d0d0264c718c5f590aaa83a3cc
Source dataset
uspto-grants-1984_07
Patent number
US04457814

Reaction notes

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