HRID147528

反应详情

EQUATION

反应方程式

HRID 147528 的结构方程式

REACTANTS

反应物

4

结构：[NH4+]

Ammonia ion (NH4+)

H4N+

结构：CO

Methanol

CH4O

结构：[OH-]

Hydroxide

HO-

结构：COc1cc2ncnc(Nc3ccc(F)c(Cl)c3)c2cc1OC(C)=O

4-(3-Chloro-4-fluoroanilino)-7-methoxyquinazolin-6-yl acetate

C17H13ClFN3O3

PRODUCTS

生成物

1

结构：COc1cc2ncnc(Nc3ccc(F)c(Cl)c3)c2cc1O

4-(3-Chloro-4-fluoroanilino)-7-methoxyquinazolin-6-ol

C15H11ClFN3O2