Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1477855Generated: October 31, 2026

Iodoethane → methyl 2-(4-(tert-butoxycarbonylamino)-1H-indazol-1-yl)-2-(4-chlorophenyl)butanoate

https://huagongshe.com/reaction/1477855

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantSodium hydrideHCID 24758—
Reactantmethyl 2-(4-(tert-butoxycarbonylamino)-1H-indazol-1-yl)-2-(4-chlorophenyl)acetateHCID 70563540—
SolventDimethylformamideHCID 6228—
Productmethyl 2-(4-(tert-butoxycarbonylamino)-1H-indazol-1-yl)-2-(4-chlorophenyl)butanoateHCID 7056296757%

Reaction Steps

The compound from step C (1 g, 2.4 mml) and EtI (42 mg, 2.6 mmol) were dissolved in anhydrous DMF (10 mL) Then NaH (144 mg, 3.6 mmol, 60%) was added to the mixture slowly at 0° C. After 30 minutes, the reaction mixture was quenched by saturate NH4Cl (10 mL), extracted with EA, dried over anhydrous Na2SO4, filtered and the filtrate was concentrated under reduced pressure. The residue was purified by silica gel column (PE: EA=20:1 to 5:1 to give the title compound (0.608 g, 57%). LC/MS m/z=444.1 [M+H]+. The two enantiomers were separated by SFC chiral separation.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09403807B2
Source datasetuspto-grants-2016_08
ORD IDord-7847df2699ac49eab561e3a14f8bcba9
Source noteuspto-grants-2016_08