HRID1479902

反应详情

EQUATION

反应方程式

HRID 1479902 的结构方程式

PROCEDURE

实验过程

Following the 2a synthetic method, using B1 (110.65 mg, 0.5 mmol) instead of A1 gave 2b white powder; (179.63 mg, 96.1%). [α]D25: +23.9 (c=0.29, CHCl3); 1H-NMR (300 MHz, acetone-d6): δ 7.76-7.72 (m, 3H), 7.39-7.22 (m, 6H), 5.04-4.98 (m, 1H), 3.44-3.26 (m, 2H), 2.48 (s, 3H); 13C NMR (300 MHz, acetone-d6): δ 171.81, 159.86, 138.26, 138.03, 136.71, 134.63, 131.56, 129.53, 128.38, 127.49, 126.86, 122.53, 122.49, 118.80, 54.13, 36.88, 20.75; HRMS (ESI): calcd for: C19H16ClNO3S [M−H]−=372.0467, obsd [M−H]−=472.0475.