HRID14880

反应详情

EQUATION

反应方程式

HRID 14880 的结构方程式

REACTANTS

反应物

2

结构：CC=O

Acetaldehyde

C2H4O

结构：CC(C)(C)OC(=O)N1CC(NCc2cccc(-c3ccnc(Cl)n3)c2)C1

未命名化合物

PRODUCTS

生成物

1

结构：CCN(Cc1cccc(-c2ccnc(Cl)n2)c1)C1CN(C(=O)OC(C)(C)C)C1

未命名化合物

PROCEDURE

实验过程

Intermediate 104 was coupled with acetaldehyde following procedure E. LC-MS showed the product had the expected M+H+ of 403.