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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1492825Generated: October 31, 2026

Iodoethane → HCID 18657889, compound

https://huagongshe.com/reaction/1492825

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantSodium hydrideHCID 24758—
ReactantHCID 57293964HCID 57293964—
SolventTetrahydrofuranHCID 8028—
ProductHCID 18657889HCID 1865788997.7%

Reaction Steps

To a solution of (2S,4R)-N-tert-butoxycarbonyl-4-tert-butyldimethylsiloxy-2-(2-pyrrolidon-4-yl)pyrrolidine (38.5 g, 0.1 mol, the compound of Reference Example 1-6) in tetrahydrofuran (200 ml) was added 60% sodium hydride in oil (4.2 g, 0.1 mol) under ice-cooling, and the mixture was stirred for 1 hour. To the mixture was added ethyl iodide (8 rag, 0.1 mol), and after stirring at room temperature overnight, the reaction mixture was concentrated. The residue was extracted with ethyl acetate (500 ml), and the mixture was washed with water (200 ml) followed by a saturated sodium chloride aqueous solution. After the extract was dried over anhydrous magnesium sulfate, the solvent was removed in vacuo, and the residue was purified by silica gel column chromatography (Wakogel™ C-300, chloroform) to obtain (2S,4R)-N-tert-butoxycarbonyl-4-tert-butyldimethylsiloxy-2-(N-ethyl-2-pyrrolidon-4-yl)pyrrolidine (40.3 g, yield: 97.7%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05374720
Source datasetuspto-grants-1994_12
ORD IDord-d428ad00eed54593bc28b49d60ccbc26
Source noteuspto-grants-1994_12