反应详情

This corresponds, given M(Cr2O3)=152 g/mol, M(Cr)=52 g/mol and M(O)=16 g/mol, to a value of 9.58 g of chromium(III) ions which the float must contain at a minimum. Based on 400 g of float, the use of chromium sulphate as tanning agent results in M(Cr2(SO4)3)=392 g/mol, M(S)=32 g/mol, M(Cr)=52 g/mol, M(O)=16 g/mol→26.53% of chromium in chromium sulphate.