HRID1511174

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID1110

Butanedioic acid

C4H6O4

HCID6342

Acetonitrile

C2H3N

结构：CNCCC(Oc1ccc(C(F)(F)F)cc1)c1ccccc1.Cl

HCID62857

Fluoxetine hydrochloride

C17H19ClF3NO

PRODUCTS

生成物

HCID1110

Butanedioic acid

C4H6O4

HCID62857

Fluoxetine hydrochloride

C17H19ClF3NO

结构：CNCCC(Oc1ccc(C(F)(F)F)cc1)c1ccccc1.Cl.O=C(O)CCC(=O)O

HCID131727182

未命名化合物

PROCEDURE

实验过程

Cocrystals of fluoxetine HCl and succinic acid were prepared as follows. In one preparation, a 458 mg sample of fluoxetine HCl was dissolved in 8 mL of acetonitrile by heating the solution gently. A 78 mg sample of succinic acid was added to the warm solution and dissolved. The solution was allowed to evaporate rapidly in a crystallization dish. Well-formed crystals as blocks formed as the solvent evaporated over 8 minutes. The product was collected on filter paper and dried to yield 401 mg of fluoxetine HCl:succinic acid (2:1) cocrystal (75% yield).

WORKUP

后处理

customIn one preparation
temperatureby heating the solution gently
dissolutiondissolved
customto evaporate rapidly in a crystallization dish
customWell-formed crystals as blocks
customformed as the solvent
customevaporated over 8 minutes
customThe product was collected
filtrationon filter paper
customdried

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-97b078d9d5814042858f2002da5674fe
来源数据集: uspto-grants-2012_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08212079B2
来源说明: uspto-grants-2012_07

反应 SMILES

[CH3:1][NH:2][CH2:3][CH2:4][CH:5]([O:12][C:13]1[CH:14]=[CH:15][C:16]([C:19]([F:22])([F:21])[F:20])=[CH:17][CH:18]=1)[C:6]1[CH:7]=[CH:8][CH:9]=[CH:10][CH:11]=1.[ClH:23].[C:24]([OH:31])(=[O:30])[CH2:25][CH2:26][C:27]([OH:29])=[O:28].C(#N)C>>[CH3:1][NH:2][CH2:3][CH2:4][CH:5]([O:12][C:13]1[CH:18]=[CH:17][C:16]([C:19]([F:20])([F:22])[F:21])=[CH:15][CH:14]=1)[C:6]1[CH:7]=[CH:8][CH:9]=[CH:10][CH:11]=1.[ClH:23].[C:24]([OH:31])(=[O:30])[CH2:25][CH2:26][C:27]([OH:29])=[O:28].[CH3:1][NH:2][CH2:3][CH2:4][CH:5]([O:12][C:13]1[CH:18]=[CH:17][C:16]([C:19]([F:20])([F:22])[F:21])=[CH:15][CH:14]=1)[C:6]1[CH:7]=[CH:8][CH:9]=[CH:10][CH:11]=1.[ClH:23].[C:24]([OH:31])(=[O:30])[CH2:25][CH2:26][C:27]([OH:29])=[O:28]