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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1511880Generated: October 27, 2026

Ethyl 2-(4-fluorophenoxy)acetate → 2-(4-Fluorophenoxy)ethanol

https://huagongshe.com/reaction/1511880

Reaction equation

Participants

RoleNameHCIDCharge
ReactantEthyl 2-(4-fluorophenoxy)acetateHCID 4476170—
ReactantAluminium lithium hydrideHCID 21226445—
SolventDiethyl EtherHCID 3283—
Product2-(4-Fluorophenoxy)ethanolHCID 57436155.3%

Reaction Conditions

Temperature0 °C

Reaction Steps

Ethyl 2-(4-fluorophenoxy)acetate (3.12 g, 15.74 mmol) was dissolved in diethyl ether (50 ml) and cooled to about 0° C. Lithium aluminum hydride (1.792 g, 47.2 mmol) was added in portions while maintaining reaction temperature below 35° C. The reaction was allowed to stir at room temperature for one hour. The crude reaction was diluted with ether (50 mL) then cooled in an ice bath and quenched by dropwise addition of water (6.1 mL), then 2 M NaOH (12.2 mL), then water (6.1 mL). The mixture was filtered and concentrated. The crude product was purified on silica gel (4:1 heptane:EtOAc as eluant) to give 2-(4-fluoro-phenoxy)-ethanol (1.36 g, 55%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08217027B2
Source datasetuspto-grants-2012_07
ORD IDord-27795e0f62704113bd527703014f144b
Source noteuspto-grants-2012_07