4-Fluoro-3-nitrobenzoic acid → 3-Amino-4-fluorobenzoic acid
Reaction equation
[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][C:3]=1[N+:11]([O-])=O.[H][H]>CO.[Pd]>[NH2:11][C:3]1[CH:4]=[C:5]([CH:9]=[CH:10][C:2]=1[F:1])[C:6]([OH:8])=[O:7]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
4-Fluoro-3-nitrobenzoic acid (270 mg, 2 mmol) and 10% Pd/C (80 mg) in MeOH (10 mL) was hydrogenated with a hydrogen balloon for 6.0 h. LC-MS indicated a completion of reaction. The mixture was filtered and the filtrate was concentrated to give 19A. 1H NMR (400 MHz, CDOD3) δ ppm 7.00 (dd, J=10.99, 8.79 Hz, 1H) 7.27-7.36 (m, 1H) 7.49 (dd, J=8.79, 2.20 Hz, 1H).
Workup
- customa completion of reaction
- filtrationThe mixture was filtered
- concentrationthe filtrate was concentrated
Sources & evidence
- ORD record
- ord-63c5009c02b94783a540e1011f4b2cb8
- Source dataset
- uspto-grants-2012_07
- Patent number
- US08222453B2
Reaction notes
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