HRID1517624

反应详情

EQUATION

反应方程式

HRID 1517624 的结构方程式

PROCEDURE

实验过程

The title compound is prepared essentially as described in Example 60 by using 2′-chloro-4′,4′-difluoro-4′,5′-dihydrospiro[piperidine-4,7′-thieno[2,3-c]pyran]hydrochloride and 1-(3-methylpyridin-2-yl)-4-formyl-pyrazole-3-carboxylate as starting materials in a 14% yield. MS (m/z): 481 (M+1).