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HRID15228

反应详情

EQUATION

反应方程式

HRID 15228 的结构方程式

REACTANTS

反应物

3
结构：Sc1ccccc1Br
HCID80598

Benzenethiol, 2-bromo-

C6H5BrS

结构：CC(C)(C)OC(=O)N1CCC(=O)CC1
HCID735900

1-Boc-4-piperidone

C10H17NO3

结构：CC(C)(C)OC(=O)N1CCC(O)(c2cc(F)ccc2S)CC1
HCID68682113

未命名化合物

PRODUCTS

生成物

1
结构：CC(C)(C)OC(=O)N1CCC(O)(c2ccccc2S)CC1
HCID68682215

未命名化合物

PROCEDURE

实验过程

This intermediate was prepared from 2-bromo-benzenethiol and 4-oxo-piperidine-1-carboxylic acid tert-butyl ester in a similar way as described for 4-(5-fluoro-2-mercapto-phenyl)-4-hydroxy-piperidine-1-carboxylic acid tert-butyl ester.