HRID1525012

反应详情

EQUATION

反应方程式

HRID 1525012 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in a manner analogous to Example 15 utilizing Intermediate 36 and Intermediate 13. MS (ESI): mass calculated for C24H23F4N7O, 501.49; m/z found 502.0 [M+H]+. 1H NMR (400 MHz, CDCl3): 8.70 (d, J=4.9, 2H), 8.38-8.31 (m, 1H), 7.24-7.17 (m, 1H), 7.14-7.02 (m, 2H), 5.86 (br s, 1H), 4.06-2.78 (m, 16H).