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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1585360Generated: October 27, 2026

1-(Bromomethyl)-4-methoxynaphthalene → 1-Methoxynaphthalene

https://huagongshe.com/reaction/1585360

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1-(Bromomethyl)-4-methoxynaphthaleneHCID 12749185—
SolventDimethylformamideHCID 6228—
Product1-MethoxynaphthaleneHCID 16668—

Reaction Steps

In analogy with Example 44, the title compound is obtained from 5(S)-(Boc-amino)-4(S)-(tert-butyldimethylsilyloxy)-6-phenyl-2(R)-[(4-methoxy-1-naphthyl)-methyl]hexanoyl-(L)-Val-N-(2-methoxyethyl)amide in abs. DMF using TB AF. [The starting compound for preparing the naphthylmethyl substituent, 1-bromomethyl-4-methoxynaphthalene, is obtained from 1-methoxynaphthalene (Fluka, Buchs, Switzerland) by brominating with I2 /Br2 in CHCl3, reacting the resulting bromide by means of a Grignard reaction and working up with CO2 to form the corresponding acid; reaction of the latter with lithium aluminium hydride to form 1-hydroxymethyl-4-methoxynaphthalene (reduction); and reaction of the latter with PBr3, thereby yielding the desired starting material (see Can. J. Chem. 59, 2629 (1981))].

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05935976
Source datasetuspto-grants-1999_08
ORD IDord-f46fa7b33dd44de9a5a3fdb4dbd466de
Source noteuspto-grants-1999_08