Sodium Methoxide → 2-(4-Octanoylphenyl)ethanol
Reaction equation
C[O-].[Na+].C([O:7][CH2:8][CH2:9][C:10]1[CH:15]=[CH:14][C:13]([C:16](=[O:24])[CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH3:23])=[CH:12][CH:11]=1)(=O)C>CO>[OH:7][CH2:8][CH2:9][C:10]1[CH:15]=[CH:14][C:13]([C:16](=[O:24])[CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH3:23])=[CH:12][CH:11]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution (18.8 ml) of 28% sodium methylate in methanol was added to a solution of the material (280 g) which contains 2-(4-octanoyl phenyl)ethyl acetate obtained in the step A as a major component in methanol (200 ml), and the solution was stirred at room temperature for 1 hour. Suspension of Amberlite IR-120B in methanol (98 ml) was added to the solution, and the mixture was filtered. The filtrate was concentrated, and the residue was recrystallized from hexane-ethyl acetate (10:1) to obtain 4′-(2-hydroxy ethyl)octanophenone (138 g) in the form of colorless crystal.
Workup
- additionwas added to the solution
- filtrationthe mixture was filtered
- concentrationThe filtrate was concentrated
- customthe residue was recrystallized from hexane-ethyl acetate (10:1)
Sources & evidence
- ORD record
- ord-55e26a1a7703437ebc44429f40a14783
- Source dataset
- uspto-grants-2001_09
- Patent number
- US06284915B1
Reaction notes
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