1-Bromo-3-chloropropane → HCID 67859889, compound

Participants

Reaction Steps

The procedures of Example 1 were followed using 4-hydroxy-3'-chlorostilbene (5.0 g, 23 mmol) and 1-bromo-3-chloropropane (4.4 mL, 43 mmol) to give 6.1 g (87%) of (E)-4-chloropropoxy-3'-chlorostilbene as an amber oil. 1NMR (CDCl3): δ7.66-6.72(m,10H), 4.11(t,2H), 3.72(t,2H), 2.22(m,2H).

Provenance & Evidence