L-Lysine → HCID 70675453, compound
Reaction equation
[CH3:1][O:2][C:3]1[C:8]([OH:9])=[CH:7][CH:6]=[C:5](/[CH:10]=[CH:11]/[C:12]([CH2:14][C:15](/[CH:17]=[CH:18]/[C:19]2[CH:27]=[C:24]([O:25][CH3:26])[C:22]([OH:23])=[CH:21][CH:20]=2)=[O:16])=[O:13])[CH:4]=1.[NH2:28][C@H:29]([C:35]([OH:37])=[O:36])[CH2:30][CH2:31][CH2:32][CH2:33][NH2:34]>CO.O>[NH2:28][C@H:29]([C:35]([OH:37])=[O:36])[CH2:30][CH2:31][CH2:32][CH2:33][NH2:34].[CH3:26][O:25][C:24]1[C:22]([OH:23])=[CH:21][CH:20]=[C:19](/[CH:18]=[CH:17]/[C:15]([CH2:14][C:12](/[CH:11]=[CH:10]/[C:5]2[CH:4]=[C:3]([O:2][CH3:1])[C:8]([OH:9])=[CH:7][CH:6]=2)=[O:13])=[O:16])[CH:27]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
For one part, 500 mg of curcumin were dissolved under heat, (0.00136M) in 50 ml of methanol (Solution 1). For the other part, 198.4 mg of lysine base (0.00136M) were dissolved in 5 ml of water (solution 2). While stirring, solution 2 was added into solution 1 and the mixture was shaken for 5 minutes and then evaporated under vacuum. The non-dissolved residue was taken back with 50 ml of ethanol and was brought to boiling point. The non-dissolved residue was then filtered out. The ethanol based solution was placed at −20° C. for one hour. The precipitate of curcumin lysinate was then collected by filtration.
Workup
- temperatureunder heat
- stirringthe mixture was shaken for 5 minutes
- customevaporated under vacuum
- filtrationThe non-dissolved residue was then filtered out
- filtrationThe precipitate of curcumin lysinate was then collected by filtration
Sources & evidence
- ORD record
- ord-5d1f8a5f7f9c42a4916acd34fd9c7b7c
- Source dataset
- uspto-grants-2014_07
- Patent number
- US08772265B2
Reaction notes
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