1-(2-Methoxyphenyl)piperazine → HCID 67999114, compound

Participants

Reaction Steps

5-(2-chloropropyl)-indolin-2-one was prepared from indolin-2-one according to the synthetic and working-up method of general procedure B. 5-(2-chloropropyl)-indolin-2-one (2.46 g, 0.011 mol) and 2-methoxyphenyl piperazine (1.92 g, 0.01 mol) were dissolved in 100 ml of acetonitrile, and triethyl amine (3.04 g, 0.03 mol) was added. A reaction under refluxing was allowed to proceed at an elevated temperature for 3 hours. Working up according to general procedure B gave 3.66 g of 5-(2-(4-(2-methoxyphenyl)piperazin-1-yl)propanoyl)indolin-2-one hydrochloride. The yield was 88.0%.

Provenance & Evidence