Aluminum(III) Chloride → HCID 20442886, compound

Participants

Reaction Steps

The procedure of Example 9 was repeated by using 334 mg of 1,5,6-tributoxy-3,6-dimethoxy-3-methyl-1,4-cyclohexadiene, 10 ml of ether and 15 mg of aluminum chloride, recovering 290 mg of an oily crude product. The crude product was purified by silica gel column chromatography using a 20:1 benzene-ethyl acetate mixture, giving 268 mg of 1,5,6-tributoxy-6 -methoxy-3-methylidene-1,4-cyclohexadiene in 89% of the theoretical yield. The compound thus obtained was identified by NMR.

Provenance & Evidence