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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1633210Generated: October 30, 2026

N-tert-Butyl-N-fluoro-4-methylbenzene-1-sulfonamide → 2-Fluoronaphthalen-1-ol

https://huagongshe.com/reaction/1633210

Reaction equation

Participants

RoleNameHCIDCharge
ReactantN-tert-Butyl-N-fluoro-4-methylbenzene-1-sulfonamideHCID 13222557—
Reactant1-Naphthalenol, potassium salt (1:1)HCID 23672323—
SolventDiethyl EtherHCID 3283—
SolventTetrahydrofuranHCID 8028—
Product2-Fluoronaphthalen-1-olHCID 276140360%

Reaction Steps

Potassium hydride (93.6 mg as a 35% oil dispersion, 0.82 mmol) was suspended in anhydrous tetrahydrofuran (2.5 mL) under nitrogen. 1-Naphthol (72 mg, 0.5 mmole) was added and the mixture was stirred until hydrogen evolution ceased (about 5 minutes) to produce potassium naphtholate. N-Fluoro-N-t-butyl-p-toluenesulfonamide (122 mg, 0.5 mmole) was dissolved in anhydrous tetrahydrofuran (2.5 mL) and the solution was added dropwise to the potassium naphtholate. After 20 minutes the reaction mixture was diluted with ether (100 mL), washed with aqueous 1N oxalic acid solution (30 mL), water (30 mL), and saturated aqueous sodium chloride solution (30 mL), and then dried over anhydrous magnesium sulfate. Filtration, removal of solvent under reduced pressure, and purification by flash column chromatography (silica, 25% methylene chloride in hexane) yielded 2-fluoro-1-naphthol (49 mg, 60% yield) as a white crystalline solid. This material, and an additional sample prepared by this procedure, were analyzed and provided the following results: 1H NMR (90 MHz, CDCl3) δ5.58 (b, 1H, OH), 7.00-8.30 (m, 6H, aromatic); 19F NMR (94.1 MHz, CDCl3) -146.78(m); HRMS calcd. for C10H7OF: 162.0480; found: 162.0439.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04479901
Source datasetuspto-grants-1984_10
ORD IDord-4faf783c4ab24594a6bad08d7597a028
Source noteuspto-grants-1984_10