HRID1634325

反应详情

EQUATION

反应方程式

HRID 1634325 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

To a solution of Compound 14 (160 mg) in CH2Cl2 (10 ml) was added an excess amount of 10% HCl-MeOH (6 ml). After the solvent was evaporated in vacuo, the residual solid was recrystallized from IPA to give Compound 15 (130 mg, 83%; three steps) as a colorless crystal.

WORKUP

后处理

  1. customAfter the solvent was evaporated in vacuo
  2. customthe residual solid was recrystallized from IPA