HRID1642963

反应详情

EQUATION

反应方程式

HRID 1642963 的结构方程式

PROCEDURE

实验过程

100 mg (0.20 mmol) of the compound from Example 184A and 52 mg (0.6 mmol) of 3-pyrrolidinol were reacted according to the General Method 6. Yield: 50 mg (55% of theory)