HRID1642992

反应详情

EQUATION

反应方程式

HRID 1642992 的结构方程式

REACTANTS

反应物

2

结构：O=C(O)C1CC(c2ccc(C(F)(F)F)cc2)CN(C(=O)N2CC(O)C2)C1

未命名化合物

结构：CC(C)OCCC(N)=NO

未命名化合物

PRODUCTS

生成物

1

结构：CC(C)OCCc1noc(C2CC(c3ccc(C(F)(F)F)cc3)CN(C(=O)N3CC(O)C3)C2)n1

未命名化合物

PROCEDURE

实验过程

100 mg (0.27 mmol) of the compound from Example 101A and 66 mg (0.40 mmol) of the compound from Example 65A were reacted according to the General Method 2. Yield: 28 mg (20% of theory)