HRID1643000

反应详情

EQUATION

反应方程式

HRID 1643000 的结构方程式

PROCEDURE

实验过程

100 mg (0.27 mmol) of the compound from Example 101A and 67 mg (0.40 mmol) of the compound from Example 67A were reacted according to the General Method 2. Yield: 33 mg (26% of theory)