HRID1643003

反应详情

EQUATION

反应方程式

HRID 1643003 的结构方程式

PROCEDURE

实验过程

100 mg (0.24 mmol) of the compound from Example 100A and 60 mg (0.37 mmol) of the compound from Example 65A were reacted according to the General Method 2. Yield: 54 mg (42% of theory)