HRID1643010

反应详情

EQUATION

反应方程式

HRID 1643010 的结构方程式

PROCEDURE

实验过程

155 mg (0.363 mmol) of the compound from Example 100A and 100 mg (0.545 mmol) of the compound from Example 75A were reacted according to the General Method 2. Yield: 76 mg (38% of theory)