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HRID1643094

反应详情

EQUATION

反应方程式

HRID 1643094 的结构方程式

REACTANTS

反应物

2
结构：OC1CCNC1
HCID98210

3-Pyrrolidinol

C4H9NO

结构：O=C(Oc1ccc([N+](=O)[O-])cc1)N1CC(c2ccc(OC(F)(F)F)cc2)CC(c2nc(C3CC3)no2)C1
HCID58002632

未命名化合物

PRODUCTS

生成物

1
结构：O=C(N1CCC(O)C1)N1CC(c2ccc(OC(F)(F)F)cc2)CC(c2nc(C3CC3)no2)C1
HCID58002509

未命名化合物

PROCEDURE

实验过程

100 mg (0.19 mmol) of the compound from Example 176A and 50 mg (0.58 mmol) of 3-pyrrolidinol were reacted according to the General Method 6. Yield: 50 mg (53% of theory)