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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1644467Generated: October 30, 2026

2,6-Lutidine → (2E)-N-(3-Bromo-5-fluorophenyl)-3-phenylacrylamide

https://huagongshe.com/reaction/1644467

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2,6-LutidineHCID 7937—
Reactant3-Phenylprop-2-enoyl chlorideHCID 66023—
Reactant(2E)-N-(3-bromophenyl)-3-phenylprop-2-enamideHCID 874919—
Reactant3-Bromo-5-fluoroanilineHCID 15020155—
Product(2E)-N-(3-Bromo-5-fluorophenyl)-3-phenylacrylamideHCID 6677473685%

Reaction Steps

The compound was prepared from 3-bromo-5-fluoroaniline (Intermediate 180, 5.3 g, 27.9 mmol) and cinnamoylchloride (5.6 g, 33.5 mmol) in the presence of 2,6-lutidine (5.0 mL, 41.9 mmol) as described for Intermediate 18 to give the product as a colorless solid, 7.6 g (85% yield).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08124602B2
Source datasetuspto-grants-2012_02
ORD IDord-db86264766014705b172ff686b8ef29e
Source noteuspto-grants-2012_02